A tool to calculate area of rectangle and also support various units.
A comprehensive guide to understand about Triangle, area of Triangle and methods to calculate area of triangle.
A triangle is a closed two-dimensional geometric shape with three straight sides and three vertices (corners). It's also known as a three-sided polygon. The sum of the interior angles of a triangle always equals 180 degrees.
The area of a triangle is a measure of the space enclosed within its three sides. Triangles are
fundamental shapes in geometry, and calculating their area is essential in various fields such
as architecture, engineering, and physics. There are several methods to calculate the area of a
triangle, depending on the given information about the triangle's sides and angles.
In this blog, we’ll explore four common methods to calculate the area of a triangle: using the
base and height, using three sides (SSS), using two sides and the angle between them (SAS), and
using two angles and the side between them (ASA). Each method will be explained with a formula
and an example.
Here, we have defined total four ways to calculate area of triangle, You can go with any one from above area of triangle calculator based on your given values.
This is the most straightforward method to calculate the area of a triangle when the base and
the corresponding height (perpendicular distance from the base to the opposite vertex) are
known. The formula is::
\( \text{Area} = \frac{\text{Base × Height}}{\text{2}}\)
The unit of area is in square units (e.g., square meters, square inches).
When all three sides of a triangle are known, Heron's formula can be used to calculate the area.
First, compute the semi-perimeter \( s \), then use it to find the area. The formulas are:
\( s = \frac{a + b + c}{2} \)
Area = \( \sqrt{s(s-a)(s-b)(s-c)} \)
where \( a \), \( b \), and \( c \) are the lengths of the sides.
Apply Heron's formula:
Area = \( \sqrt{6(6-3)(6-4)(6-5)} = \sqrt{6 \times 3 \times 2 \times 1} \)
Area = \( \sqrt{36} = 6 \) square meters
If two sides and the angle between them are known, the area can be calculated using the sine of
the angle. The formula is:
Area = \( \frac{1}{2} \times a \times b \times \sin(\theta) \)
where \( a \) and \( b \) are the two sides, and \( \theta \) is the angle between them (in radians). If the angle is given in degrees, convert it to radians using \( \text{radians} = \text{degrees} \times \frac{\pi}{180} \).
Apply the formula:
Area = \( \frac{1}{2} \times 4 \times 5 \times \sin(30^\circ) \)
Area = \( \frac{1}{2} \times 4 \times 5 \times 0.5 = 5 \) square meters
So, the area of the triangle is 5 square meters.
When two angles and the side between them are known, we can find the area by first calculating
the third angle, then using the Law of Sines to find the other sides, and finally applying the
area formula with two sides and the included angle. The steps are:
Third angle: \( \gamma = 180^\circ - \alpha - \beta \)
Use Law of Sines: \( \frac{c}{\sin(\gamma)} = \frac{a}{\sin(\alpha)} = \frac{b}{\sin(\beta)} \)
Area: \( \text{Area} = \frac{1}{2} \times a \times b \times \sin(\gamma) \)
Use the Law of Sines to find the other sides:
Let the side between the angles be \( c \). Then:
\( \frac{c}{\sin(\gamma)} = \frac{a}{\sin(\alpha)} \)
\( a = \frac{c \times \sin(\alpha)}{\sin(\gamma)} = \frac{4 \times \sin(30^\circ)}{\sin(90^\circ)} = \frac{4 \times 0.5}{1} = 2 \) meters
\( b = \frac{c \times \sin(\beta)}{\sin(\gamma)} = \frac{4 \times \sin(60^\circ)}{\sin(90^\circ)} = \frac{4 \times \frac{\sqrt{3}}{2}}{1} \approx 3.46 \) meters
Calculate the area::
Area = \( \frac{1}{2} \times a \times b \times \sin(\gamma) \).
Area = \( \frac{1}{2} \times 2 \times 3.46 \times \sin(90^\circ)\)
Area \( \approx \frac{1}{2} \times 2 \times 3.46 \times 1 \approx 3.46 \) square meters So, the area of the triangle is approximately 3.46 square meters.